Webcamxp 5 Shodan Search Free ◉

def fetch_title(url, timeout=8): headers = {"User-Agent": "Mozilla/5.0 (compatible)"} try: r = requests.get(url, headers=headers, timeout=timeout) if r.status_code == 200 and 'text/html' in r.headers.get('Content-Type',''): start = r.text.find('<title>') end = r.text.find('</title>', start) if start!=-1 and end!=-1: return r.text[start+7:end].strip() return None except Exception as e: return None